2 Dakika Kural için C# StructuralComparisons Nedir

2 Dakika Kural için C# StructuralComparisons Nedir

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I am trying to have struct bey a property in my class, and want to check to see if the struct is equal to the value I am trying to assign it to, before I go ahead and do so, so I am derece indicating the property has changed when it hasn't, like so:

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I want to know what for is StructuralComparisons Class present in System.Collections used and also how is it used?I have no idea how should I use it!! Smallest help would be appreciated.

Ekseriyetle cılız muta gruplarını simgeleme buyurmak ciğerin yahut performans eleştiri kodlarda yeğleme edilir.

The StructuralComparisons.StructuralEqualityComparer version require that the two collections can support the IStructuralEquatable interface. But I would expect that the later is faster if the two lists are uneven lengths.

So to sum up, the implementation for both is kind of the same, both iterate two array based on value equality of int to make comparison.

The IStructuralEquatable interface enables you to implement customized comparisons to check for the structural equality of collection objects. This C# StructuralComparisons Kullanımı is also made clear by the fact that this interface resides in the System.Collections namespace.

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C# C# StructuralComparisons Temel Özellikleri IStructuralEquatable arabirimi, koleksiyonların konstrüktif eşitliğini tarif etmek sinein kullanılır. İki nesnenin gönülğinin aynı olup olmadığını belirlemek ve bu nesnelerin önlaştırılabilirliğini çıkarmak için önemli yöntemler sunar.

Koleksiyonların Strüktürel Kontralaştırması: IStructuralEquatable arabirimi, özellikle diziler ve koleksiyonlar gibi konstrüktif bilgi binalarının katlaştırılması yürekin kullanılır.

You hayat then specify that this definition be used with a collection type that accepts the IStructuralComparable interface.

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For example, An implementation of IStructureComparable for a list would only need to scan a flat list whereas an implementation for a binary tree would also need to take into account the branching of the tree (e.